Example 5.  Consider the function  [Graphics:Images/TaylorPolyMod_gr_348.gif].  
5 (c).  Find the terms up to  [Graphics:Images/TaylorPolyMod_gr_351.gif]  in the Maclaurin series and see how close it approximates  f[x].
Solution 5 (c).

5 (c).  Find the terms up to  [Graphics:../Images/TaylorPolyMod_gr_408.gif]  in the Maclaurin series and see how close it approximates  f[x].

Go ahead "enjoy" and add terms in the series up to [Graphics:../Images/TaylorPolyMod_gr_409.gif], then plot the functions over the interval [-3.0, 3.0].

[Graphics:../Images/TaylorPolyMod_gr_410.gif]

[Graphics:../Images/TaylorPolyMod_gr_411.gif]

[Graphics:../Images/TaylorPolyMod_gr_412.gif]

Question.  Do we have a "good approximation" on the interval  [-3.0, 3.0] ?

[Graphics:../Images/TaylorPolyMod_gr_413.gif]

[Graphics:../Images/TaylorPolyMod_gr_414.gif]

[Graphics:../Images/TaylorPolyMod_gr_415.gif]

[Graphics:../Images/TaylorPolyMod_gr_416.gif]

Aside.  Mathematica actually computes the higher derivatives of f[x] up to the order 50 when calculating the Taylor series. Suppose you had to find the formula for the first 20 derivatives of f[x].  Could "you" do it ?  Would you want to do it ?

[Graphics:../Images/TaylorPolyMod_gr_417.gif]


[Graphics:../Images/TaylorPolyMod_gr_418.gif]


[Graphics:../Images/TaylorPolyMod_gr_419.gif]


[Graphics:../Images/TaylorPolyMod_gr_420.gif]

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) John H. Mathews 2004