Example
13. Let
over
. Use
the Upper Riemann Sum to approximate the value of the integral.
Solution 13.
Remark. This will
be slow because many minimums need to be approximated.
You can skip the calculation and look at the recorded results. Change
4 to
20 to get all
of the table.
|
m sample points |
UpperRiemann[a,b,m] |
|
1 |
|
|
2 |
|
|
4 |
|
|
6 |
|
|
8 |
|
|
10 |
|
|
12 |
|
|
14 |
|
|
16 |
|
|
20 |
|
|
24 |
|
|
28 |
|
|
32 |
|
|
40 |
|
|
50 |
|
|
60 |
|
|
70 |
|
|
80 |
|
|
100 |
|
|
120 |
|
![[Graphics:../Images/RiemannSumMod_gr_278.gif]](../Images/RiemannSumMod_gr_278.gif)
![[Graphics:../Images/RiemannSumMod_gr_279.gif]](../Images/RiemannSumMod_gr_279.gif)
Animation 4. ( Upper Riemann Sum Upper Riemann Sum ). Internet hyperlink.
(c) John H. Mathews 2004