Example 2. Consider
the closed five sector economy
consisting of say: Agriculture, Construction, Energy, Manufacturing,
and Services where the input-output matrix is given by
. Find the production vector
.
Solution 2.
Enter the matrix
.
If
is an eigenvalue of
and
an
eigen-pair, then the solution to
will be a multiple of the eigenvector
.
Let us verify that
is an eigenvalue
of
.
The eigen-pair
is
easily computed using Mathematica's
subroutines Eigenvalues
and Eigenvectors.
Since
is
a solution for any constant c,
we are permitted to choose any multiple
of
we desire for the solution. For illustration:
Aside. Any value
of c is
permitted, it is your choice. When
we get
We are done.
How did we get that "nice" vector ?
By using exact arithmetic and the following calculations.
Form the homogeneous system
.
and the augmented matrix
and
find its reduced row echelon form.
![[Graphics:../Images/LeontiefModelMod_gr_109.gif]](../Images/LeontiefModelMod_gr_109.gif)
The equations for this augmented matrix are
There is one free variables which we choose to
be
. It
is used in computing
.
Use
and solve the previous equations for
Get
![[Graphics:../Images/LeontiefModelMod_gr_116.gif]](../Images/LeontiefModelMod_gr_116.gif)
The solution vector
is
We are done.
Aside. We can
verify that this is the solution by direct multiplication A
X. This is just for fun !
We are really done.
Aside. Iteration
can be used to solve for the solution of the closed Leontief
model. If the sum of the production levels is known and a
starting vector is given
then the simple iteration
will
converge to
. Because
the largest eigenvalue is
, this
is a simplified version of the "power method" for finding
the dominant eigen-pair. For the example
above
and the following iteration will converge.
(c) John H. Mathews 2004