Example
5. Use the
determinant method to find the standard equation of a parabola
through the points
(6,1), (2,2) and (1,4).
Remark.
In Exercises 4 and 6 the same points are used to find the circle and
alternate parabola.
Solution 5.
The points are entered into Mathematica with the command:
Then a row vector corresponding to equation (5) is defined:
The matrix A for the linear system in (6) and the determinant is now created. The vector R is stored in the first row by issuing the command A = {R}. Then the remaining three rows of A are generated with the loop command:
For the given three points, the homogeneous system AC = 0 is:
![[Graphics:../Images/ConicFitMod_gr_57.gif]](../Images/ConicFitMod_gr_57.gif)
The determinant of this matrix is computed by typing:
The desired equation is:
The conic is the standard parabola shown in Figure 5. It is plotted using the commands:
![[Graphics:../Images/ConicFitMod_gr_63.gif]](../Images/ConicFitMod_gr_63.gif)
(c) John H. Mathews 2004