The Mobius Transformation

 

Example 10.7. Find the bilinear transformation w = S(z) that maps
the crescent-shaped region that lies inside the disk |z-2| < 2 and outside the circle
|z-1| = 1 onto a horizontal strip.

Solution. For convenience we choose [Graphics:m6.txtgr1.gif]
which are mapped onto the points [Graphics:m6.txtgr2.gif], respectively.
In this case we remove the terms involving [Graphics:m6.txtgr3.gif], in the implicit formula,
because this implies that [Graphics:m6.txtgr4.gif].

[Graphics:m6.txtgr6.gif][Graphics:m6.txtgr5.gif]

Check our work and look at the images of [Graphics:m6.txtgr7.gif].

[Graphics:m6.txtgr6.gif][Graphics:m6.txtgr8.gif]

And we need to look at the points [Graphics:m6.txtgr9.gif].

[Graphics:m6.txtgr6.gif][Graphics:m6.txtgr10.gif]

To illustrate the mapping, consider the inverse image of the horizontal strip,
and the mapping [Graphics:m6.txtgr11.gif].

The Mobius transformation w = (-iz + 4i)/z. 

 

 

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(c) John Mathews, 1998, 2006